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33 lines
586 B
33 lines
586 B
2 years ago
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1480. Running Sum of 1d Array
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Easy
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Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]).
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Return the running sum of nums.
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Example 1:
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Input: nums = [1,2,3,4]
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Output: [1,3,6,10]
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Explanation: Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4].
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Example 2:
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Input: nums = [1,1,1,1,1]
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Output: [1,2,3,4,5]
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Explanation: Running sum is obtained as follows: [1, 1+1, 1+1+1, 1+1+1+1, 1+1+1+1+1].
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Example 3:
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Input: nums = [3,1,2,10,1]
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Output: [3,4,6,16,17]
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Constraints:
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1 <= nums.length <= 1000
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-10^6 <= nums[i] <= 10^6
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