lastword

lastword/lastword.go

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+package lastword
+
+import "strings"
+
+func LengthOfLastWord(s string) int {
+	return lengthOfLastWord(s)
+}
+
+func lengthOfLastWord(s string) int {
+	words := strings.Fields(s)
+	if len(words) == 0 {
+		return 0
+	}
+	return len(words[len(words)-1])
+}

lastword/lastword_test.go

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+package lastword_test
+
+import (
+	"testing"
+
+	"git.jxs.me/leetgo/lastword"
+	"github.com/stretchr/testify/require"
+)
+
+func TestExamples(t *testing.T) {
+	cases := map[string]int{
+		"":                    0,
+		"hello":               5,
+		"hello computer":      8,
+		" goodbye my friend ": 6,
+	}
+	for input, expected := range cases {
+		t.Run(input, func(t *testing.T) {
+			result := lastword.LengthOfLastWord(input)
+			require.Equal(t, expected, result)
+		})
+	}
+}

lastword/readme.md

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+58. Length of Last Word
+Easy
+
+Given a string s consisting of words and spaces, return the length of the last word in the string.
+
+A word is a maximal substring consisting of non-space characters only.
+
+ 
+Example 1:
+
+```
+Input: s = "Hello World"
+Output: 5
+Explanation: The last word is "World" with length 5.
+```
+
+Example 2:
+
+```
+Input: s = "   fly me   to   the moon  "
+Output: 4
+Explanation: The last word is "moon" with length 4.
+```
+
+Example 3:
+
+```
+Input: s = "luffy is still joyboy"
+Output: 6
+Explanation: The last word is "joyboy" with length 6.
+```
+
+Constraints:
+
+    1 <= s.length <= 104
+    s consists of only English letters and spaces ' '.
+    There will be at least one word in s.