break palindrome

Jason Staten 2 years ago
parent c3be3cb705
commit b8c2a2e5cd

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package breakpalindrome
func breakPalindrome(palindrome string) string {
if len(palindrome) <= 1 {
return ""
result := []rune(palindrome)
for i, r := range result {
if r != 'a' {
result[i] = 'a'
for _, r := range result {
if r != 'a' {
return string(result)
return palindrome[:len(palindrome)-1] + "b"
func Break(palindrome string) string {
return breakPalindrome(palindrome)

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package breakpalindrome_test
import (
bp ""
func TestEmpty(t *testing.T) {
require.Equal(t, "", bp.Break(""))
func TestSingle(t *testing.T) {
require.Equal(t, "", bp.Break("a"))
func TestShort(t *testing.T) {
require.Equal(t, "aaccba", bp.Break("abccba"))
func TestAllA(t *testing.T) {
require.Equal(t, "aaaab", bp.Break("aaaaa"))

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1328. Break a Palindrome
Given a palindromic string of lowercase English letters palindrome, replace exactly one character with any lowercase English letter so that the resulting string is not a palindrome and that it is the lexicographically smallest one possible.
Return the resulting string. If there is no way to replace a character to make it not a palindrome, return an empty string.
A string a is lexicographically smaller than a string b (of the same length) if in the first position where a and b differ, a has a character strictly smaller than the corresponding character in b. For example, "abcc" is lexicographically smaller than "abcd" because the first position they differ is at the fourth character, and 'c' is smaller than 'd'.
Example 1:
Input: palindrome = "abccba"
Output: "aaccba"
Explanation: There are many ways to make "abccba" not a palindrome, such as "zbccba", "aaccba", and "abacba".
Of all the ways, "aaccba" is the lexicographically smallest.
Example 2:
Input: palindrome = "a"
Output: ""
Explanation: There is no way to replace a single character to make "a" not a palindrome, so return an empty string.
1 <= palindrome.length <= 1000
palindrome consists of only lowercase English letters.